2 * Copyright © 2010 Intel Corporation
4 * Permission is hereby granted, free of charge, to any person obtaining a
5 * copy of this software and associated documentation files (the "Software"),
6 * to deal in the Software without restriction, including without limitation
7 * the rights to use, copy, modify, merge, publish, distribute, sublicense,
8 * and/or sell copies of the Software, and to permit persons to whom the
9 * Software is furnished to do so, subject to the following conditions:
11 * The above copyright notice and this permission notice (including the next
12 * paragraph) shall be included in all copies or substantial portions of the
15 * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
16 * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
17 * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL
18 * THE AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
19 * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING
20 * FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS
24 * Eric Anholt <eric@anholt.net>
28 /** @file register_allocate.c
30 * Graph-coloring register allocator.
32 * The basic idea of graph coloring is to make a node in a graph for
33 * every thing that needs a register (color) number assigned, and make
34 * edges in the graph between nodes that interfere (can't be allocated
35 * to the same register at the same time).
37 * During the "simplify" process, any any node with fewer edges than
38 * there are registers means that that edge can get assigned a
39 * register regardless of what its neighbors choose, so that node is
40 * pushed on a stack and removed (with its edges) from the graph.
41 * That likely causes other nodes to become trivially colorable as well.
43 * Then during the "select" process, nodes are popped off of that
44 * stack, their edges restored, and assigned a color different from
45 * their neighbors. Because they were pushed on the stack only when
46 * they were trivially colorable, any color chosen won't interfere
47 * with the registers to be popped later.
49 * The downside to most graph coloring is that real hardware often has
50 * limitations, like registers that need to be allocated to a node in
51 * pairs, or aligned on some boundary. This implementation follows
52 * the paper "Retargetable Graph-Coloring Register Allocation for
53 * Irregular Architectures" by Johan Runeson and Sven-Olof Nyström.
55 * In this system, there are register classes each containing various
56 * registers, and registers may interfere with other registers. For
57 * example, one might have a class of base registers, and a class of
58 * aligned register pairs that would each interfere with their pair of
59 * the base registers. Each node has a register class it needs to be
60 * assigned to. Define p(B) to be the size of register class B, and
61 * q(B,C) to be the number of registers in B that the worst choice
62 * register in C could conflict with. Then, this system replaces the
63 * basic graph coloring test of "fewer edges from this node than there
64 * are registers" with "For this node of class B, the sum of q(B,C)
65 * for each neighbor node of class C is less than pB".
67 * A nice feature of the pq test is that q(B,C) can be computed once
68 * up front and stored in a 2-dimensional array, so that the cost of
69 * coloring a node is constant with the number of registers. We do
70 * this during ra_set_finalize().
76 #include "main/imports.h"
77 #include "main/macros.h"
78 #include "main/mtypes.h"
79 #include "util/bitset.h"
80 #include "register_allocate.h"
85 BITSET_WORD *conflicts;
86 unsigned int *conflict_list;
87 unsigned int conflict_list_size;
88 unsigned int num_conflicts;
95 struct ra_class **classes;
96 unsigned int class_count;
103 * Bitset indicating which registers belong to this class.
105 * (If bit N is set, then register N belongs to this class.)
110 * p(B) in Runeson/Nyström paper.
112 * This is "how many regs are in the set."
117 * q(B,C) (indexed by C, B is this register class) in
118 * Runeson/Nyström paper. This is "how many registers of B could
119 * the worst choice register from C conflict with".
127 * List of which nodes this node interferes with. This should be
128 * symmetric with the other node.
130 BITSET_WORD *adjacency;
131 unsigned int *adjacency_list;
132 unsigned int adjacency_list_size;
133 unsigned int adjacency_count;
138 /* Register, if assigned, or NO_REG. */
142 * Set when the node is in the trivially colorable stack. When
143 * set, the adjacency to this node is ignored, to implement the
144 * "remove the edge from the graph" in simplification without
145 * having to actually modify the adjacency_list.
150 * The q total, as defined in the Runeson/Nyström paper, for all the
151 * interfering nodes not in the stack.
153 unsigned int q_total;
155 /* For an implementation that needs register spilling, this is the
156 * approximate cost of spilling this node.
162 struct ra_regs *regs;
164 * the variables that need register allocation.
166 struct ra_node *nodes;
167 unsigned int count; /**< count of nodes. */
170 unsigned int stack_count;
173 * Tracks the start of the set of optimistically-colored registers in the
176 unsigned int stack_optimistic_start;
180 * Creates a set of registers for the allocator.
182 * mem_ctx is a ralloc context for the allocator. The reg set may be freed
183 * using ralloc_free().
186 ra_alloc_reg_set(void *mem_ctx, unsigned int count, bool need_conflict_lists)
189 struct ra_regs *regs;
191 regs = rzalloc(mem_ctx, struct ra_regs);
193 regs->regs = rzalloc_array(regs, struct ra_reg, count);
195 for (i = 0; i < count; i++) {
196 regs->regs[i].conflicts = rzalloc_array(regs->regs, BITSET_WORD,
197 BITSET_WORDS(count));
198 BITSET_SET(regs->regs[i].conflicts, i);
200 if (need_conflict_lists) {
201 regs->regs[i].conflict_list = ralloc_array(regs->regs,
203 regs->regs[i].conflict_list_size = 4;
204 regs->regs[i].conflict_list[0] = i;
206 regs->regs[i].conflict_list = NULL;
207 regs->regs[i].conflict_list_size = 0;
209 regs->regs[i].num_conflicts = 1;
216 * The register allocator by default prefers to allocate low register numbers,
217 * since it was written for hardware (gen4/5 Intel) that is limited in its
218 * multithreadedness by the number of registers used in a given shader.
220 * However, for hardware without that restriction, densely packed register
221 * allocation can put serious constraints on instruction scheduling. This
222 * function tells the allocator to rotate around the registers if possible as
223 * it allocates the nodes.
226 ra_set_allocate_round_robin(struct ra_regs *regs)
228 regs->round_robin = true;
232 ra_add_conflict_list(struct ra_regs *regs, unsigned int r1, unsigned int r2)
234 struct ra_reg *reg1 = ®s->regs[r1];
236 if (reg1->conflict_list) {
237 if (reg1->conflict_list_size == reg1->num_conflicts) {
238 reg1->conflict_list_size *= 2;
239 reg1->conflict_list = reralloc(regs->regs, reg1->conflict_list,
240 unsigned int, reg1->conflict_list_size);
242 reg1->conflict_list[reg1->num_conflicts++] = r2;
244 BITSET_SET(reg1->conflicts, r2);
248 ra_add_reg_conflict(struct ra_regs *regs, unsigned int r1, unsigned int r2)
250 if (!BITSET_TEST(regs->regs[r1].conflicts, r2)) {
251 ra_add_conflict_list(regs, r1, r2);
252 ra_add_conflict_list(regs, r2, r1);
257 * Adds a conflict between base_reg and reg, and also between reg and
258 * anything that base_reg conflicts with.
260 * This can simplify code for setting up multiple register classes
261 * which are aggregates of some base hardware registers, compared to
262 * explicitly using ra_add_reg_conflict.
265 ra_add_transitive_reg_conflict(struct ra_regs *regs,
266 unsigned int base_reg, unsigned int reg)
270 ra_add_reg_conflict(regs, reg, base_reg);
272 for (i = 0; i < regs->regs[base_reg].num_conflicts; i++) {
273 ra_add_reg_conflict(regs, reg, regs->regs[base_reg].conflict_list[i]);
278 * Makes every conflict on the given register transitive. In other words,
279 * every register that conflicts with r will now conflict with every other
280 * register conflicting with r.
282 * This can simplify code for setting up multiple register classes
283 * which are aggregates of some base hardware registers, compared to
284 * explicitly using ra_add_reg_conflict.
287 ra_make_reg_conflicts_transitive(struct ra_regs *regs, unsigned int r)
289 struct ra_reg *reg = ®s->regs[r];
293 BITSET_FOREACH_SET(c, tmp, reg->conflicts, regs->count) {
294 struct ra_reg *other = ®s->regs[c];
296 for (i = 0; i < BITSET_WORDS(regs->count); i++)
297 other->conflicts[i] |= reg->conflicts[i];
302 ra_alloc_reg_class(struct ra_regs *regs)
304 struct ra_class *class;
306 regs->classes = reralloc(regs->regs, regs->classes, struct ra_class *,
307 regs->class_count + 1);
309 class = rzalloc(regs, struct ra_class);
310 regs->classes[regs->class_count] = class;
312 class->regs = rzalloc_array(class, BITSET_WORD, BITSET_WORDS(regs->count));
314 return regs->class_count++;
318 ra_class_add_reg(struct ra_regs *regs, unsigned int c, unsigned int r)
320 struct ra_class *class = regs->classes[c];
322 BITSET_SET(class->regs, r);
327 * Returns true if the register belongs to the given class.
330 reg_belongs_to_class(unsigned int r, struct ra_class *c)
332 return BITSET_TEST(c->regs, r);
336 * Must be called after all conflicts and register classes have been
337 * set up and before the register set is used for allocation.
338 * To avoid costly q value computation, use the q_values paramater
339 * to pass precomputed q values to this function.
342 ra_set_finalize(struct ra_regs *regs, unsigned int **q_values)
346 for (b = 0; b < regs->class_count; b++) {
347 regs->classes[b]->q = ralloc_array(regs, unsigned int, regs->class_count);
351 for (b = 0; b < regs->class_count; b++) {
352 for (c = 0; c < regs->class_count; c++) {
353 regs->classes[b]->q[c] = q_values[b][c];
357 /* Compute, for each class B and C, how many regs of B an
358 * allocation to C could conflict with.
360 for (b = 0; b < regs->class_count; b++) {
361 for (c = 0; c < regs->class_count; c++) {
363 int max_conflicts = 0;
365 for (rc = 0; rc < regs->count; rc++) {
369 if (!reg_belongs_to_class(rc, regs->classes[c]))
372 for (i = 0; i < regs->regs[rc].num_conflicts; i++) {
373 unsigned int rb = regs->regs[rc].conflict_list[i];
374 if (reg_belongs_to_class(rb, regs->classes[b]))
377 max_conflicts = MAX2(max_conflicts, conflicts);
379 regs->classes[b]->q[c] = max_conflicts;
384 for (b = 0; b < regs->count; b++) {
385 ralloc_free(regs->regs[b].conflict_list);
386 regs->regs[b].conflict_list = NULL;
391 ra_add_node_adjacency(struct ra_graph *g, unsigned int n1, unsigned int n2)
393 BITSET_SET(g->nodes[n1].adjacency, n2);
396 int n1_class = g->nodes[n1].class;
397 int n2_class = g->nodes[n2].class;
398 g->nodes[n1].q_total += g->regs->classes[n1_class]->q[n2_class];
401 if (g->nodes[n1].adjacency_count >=
402 g->nodes[n1].adjacency_list_size) {
403 g->nodes[n1].adjacency_list_size *= 2;
404 g->nodes[n1].adjacency_list = reralloc(g, g->nodes[n1].adjacency_list,
406 g->nodes[n1].adjacency_list_size);
409 g->nodes[n1].adjacency_list[g->nodes[n1].adjacency_count] = n2;
410 g->nodes[n1].adjacency_count++;
414 ra_alloc_interference_graph(struct ra_regs *regs, unsigned int count)
419 g = rzalloc(NULL, struct ra_graph);
421 g->nodes = rzalloc_array(g, struct ra_node, count);
424 g->stack = rzalloc_array(g, unsigned int, count);
426 for (i = 0; i < count; i++) {
427 int bitset_count = BITSET_WORDS(count);
428 g->nodes[i].adjacency = rzalloc_array(g, BITSET_WORD, bitset_count);
430 g->nodes[i].adjacency_list_size = 4;
431 g->nodes[i].adjacency_list =
432 ralloc_array(g, unsigned int, g->nodes[i].adjacency_list_size);
433 g->nodes[i].adjacency_count = 0;
434 g->nodes[i].q_total = 0;
436 ra_add_node_adjacency(g, i, i);
437 g->nodes[i].reg = NO_REG;
444 ra_set_node_class(struct ra_graph *g,
445 unsigned int n, unsigned int class)
447 g->nodes[n].class = class;
451 ra_add_node_interference(struct ra_graph *g,
452 unsigned int n1, unsigned int n2)
454 if (!BITSET_TEST(g->nodes[n1].adjacency, n2)) {
455 ra_add_node_adjacency(g, n1, n2);
456 ra_add_node_adjacency(g, n2, n1);
461 pq_test(struct ra_graph *g, unsigned int n)
463 int n_class = g->nodes[n].class;
465 return g->nodes[n].q_total < g->regs->classes[n_class]->p;
469 decrement_q(struct ra_graph *g, unsigned int n)
472 int n_class = g->nodes[n].class;
474 for (i = 0; i < g->nodes[n].adjacency_count; i++) {
475 unsigned int n2 = g->nodes[n].adjacency_list[i];
476 unsigned int n2_class = g->nodes[n2].class;
478 if (n != n2 && !g->nodes[n2].in_stack) {
479 assert(g->nodes[n2].q_total >= g->regs->classes[n2_class]->q[n_class]);
480 g->nodes[n2].q_total -= g->regs->classes[n2_class]->q[n_class];
486 * Simplifies the interference graph by pushing all
487 * trivially-colorable nodes into a stack of nodes to be colored,
488 * removing them from the graph, and rinsing and repeating.
490 * If we encounter a case where we can't push any nodes on the stack, then
491 * we optimistically choose a node and push it on the stack. We heuristically
492 * push the node with the lowest total q value, since it has the fewest
493 * neighbors and therefore is most likely to be allocated.
496 ra_simplify(struct ra_graph *g)
498 bool progress = true;
499 unsigned int stack_optimistic_start = UINT_MAX;
503 unsigned int best_optimistic_node = ~0;
504 unsigned int lowest_q_total = ~0;
508 for (i = g->count - 1; i >= 0; i--) {
509 if (g->nodes[i].in_stack || g->nodes[i].reg != NO_REG)
514 g->stack[g->stack_count] = i;
516 g->nodes[i].in_stack = true;
519 unsigned int new_q_total = g->nodes[i].q_total;
520 if (new_q_total < lowest_q_total) {
521 best_optimistic_node = i;
522 lowest_q_total = new_q_total;
527 if (!progress && best_optimistic_node != ~0U) {
528 if (stack_optimistic_start == UINT_MAX)
529 stack_optimistic_start = g->stack_count;
531 decrement_q(g, best_optimistic_node);
532 g->stack[g->stack_count] = best_optimistic_node;
534 g->nodes[best_optimistic_node].in_stack = true;
539 g->stack_optimistic_start = stack_optimistic_start;
543 ra_any_neighbors_conflict(struct ra_graph *g, unsigned int n, unsigned int r)
547 for (i = 0; i < g->nodes[n].adjacency_count; i++) {
548 unsigned int n2 = g->nodes[n].adjacency_list[i];
550 if (!g->nodes[n2].in_stack &&
551 BITSET_TEST(g->regs->regs[r].conflicts, g->nodes[n2].reg)) {
560 * Pops nodes from the stack back into the graph, coloring them with
561 * registers as they go.
563 * If all nodes were trivially colorable, then this must succeed. If
564 * not (optimistic coloring), then it may return false;
567 ra_select(struct ra_graph *g)
569 int start_search_reg = 0;
571 while (g->stack_count != 0) {
574 int n = g->stack[g->stack_count - 1];
575 struct ra_class *c = g->regs->classes[g->nodes[n].class];
577 /* Find the lowest-numbered reg which is not used by a member
578 * of the graph adjacent to us.
580 for (ri = 0; ri < g->regs->count; ri++) {
581 r = (start_search_reg + ri) % g->regs->count;
582 if (!reg_belongs_to_class(r, c))
585 if (!ra_any_neighbors_conflict(g, n, r))
589 /* set this to false even if we return here so that
590 * ra_get_best_spill_node() considers this node later.
592 g->nodes[n].in_stack = false;
594 if (ri == g->regs->count)
600 /* Rotate the starting point except for any nodes above the lowest
601 * optimistically colorable node. The likelihood that we will succeed
602 * at allocating optimistically colorable nodes is highly dependent on
603 * the way that the previous nodes popped off the stack are laid out.
604 * The round-robin strategy increases the fragmentation of the register
605 * file and decreases the number of nearby nodes assigned to the same
606 * color, what increases the likelihood of spilling with respect to the
607 * dense packing strategy.
609 if (g->regs->round_robin &&
610 g->stack_count - 1 <= g->stack_optimistic_start)
611 start_search_reg = r + 1;
618 ra_allocate(struct ra_graph *g)
625 ra_get_node_reg(struct ra_graph *g, unsigned int n)
627 return g->nodes[n].reg;
631 * Forces a node to a specific register. This can be used to avoid
632 * creating a register class containing one node when handling data
633 * that must live in a fixed location and is known to not conflict
634 * with other forced register assignment (as is common with shader
635 * input data). These nodes do not end up in the stack during
636 * ra_simplify(), and thus at ra_select() time it is as if they were
637 * the first popped off the stack and assigned their fixed locations.
638 * Nodes that use this function do not need to be assigned a register
641 * Must be called before ra_simplify().
644 ra_set_node_reg(struct ra_graph *g, unsigned int n, unsigned int reg)
646 g->nodes[n].reg = reg;
647 g->nodes[n].in_stack = false;
651 ra_get_spill_benefit(struct ra_graph *g, unsigned int n)
655 int n_class = g->nodes[n].class;
657 /* Define the benefit of eliminating an interference between n, n2
658 * through spilling as q(C, B) / p(C). This is similar to the
659 * "count number of edges" approach of traditional graph coloring,
660 * but takes classes into account.
662 for (j = 0; j < g->nodes[n].adjacency_count; j++) {
663 unsigned int n2 = g->nodes[n].adjacency_list[j];
665 unsigned int n2_class = g->nodes[n2].class;
666 benefit += ((float)g->regs->classes[n_class]->q[n2_class] /
667 g->regs->classes[n_class]->p);
675 * Returns a node number to be spilled according to the cost/benefit using
676 * the pq test, or -1 if there are no spillable nodes.
679 ra_get_best_spill_node(struct ra_graph *g)
681 unsigned int best_node = -1;
682 float best_benefit = 0.0;
685 /* Consider any nodes that we colored successfully or the node we failed to
686 * color for spilling. When we failed to color a node in ra_select(), we
687 * only considered these nodes, so spilling any other ones would not result
688 * in us making progress.
690 for (n = 0; n < g->count; n++) {
691 float cost = g->nodes[n].spill_cost;
697 if (g->nodes[n].in_stack)
700 benefit = ra_get_spill_benefit(g, n);
702 if (benefit / cost > best_benefit) {
703 best_benefit = benefit / cost;
712 * Only nodes with a spill cost set (cost != 0.0) will be considered
713 * for register spilling.
716 ra_set_node_spill_cost(struct ra_graph *g, unsigned int n, float cost)
718 g->nodes[n].spill_cost = cost;