binop/2addr

Purpose

Perform the identified binary operation on the two source registers, storing the result in the first source register.

Details

Op & Format	Mnemonic / Syntax	Arguments
b0..cf 12x	binop/2addr vA, vB b0: add-int/2addr b1: sub-int/2addr b2: mul-int/2addr b3: div-int/2addr b4: rem-int/2addr b5: and-int/2addr b6: or-int/2addr b7: xor-int/2addr b8: shl-int/2addr b9: shr-int/2addr ba: ushr-int/2addr bb: add-long/2addr bc: sub-long/2addr bd: mul-long/2addr be: div-long/2addr bf: rem-long/2addr c0: and-long/2addr c1: or-long/2addr c2: xor-long/2addr c3: shl-long/2addr c4: shr-long/2addr c5: ushr-long/2addr c6: add-float/2addr c7: sub-float/2addr c8: mul-float/2addr c9: div-float/2addr ca: rem-float/2addr cb: add-double/2addr cc: sub-double/2addr cd: mul-double/2addr ce: div-double/2addr cf: rem-double/2addr	`A:` destination and first source register or pair (4 bits) `B:` second source register or pair (4 bits)

Constraints

Both A and B must be valid register indices in the current stackframe.
For the -long and -double variants, also A+1 and B+1 must be valid register indices.
Registers vA and vB must be defined. They must both contain values that match the variant of the instruction (it's probably better to split this up into multiple pages again).

Behavior

The given operation <binop> is performed according to the semantics specified in table XXX.
The result is stored in register vA, that is, vA'=vA <binop> vB.
For the -double and -long variants, (vA+1) is also affected.
As usual, neighboring registers might get undefined, if vA (and vA+1) were part of a register pair originally.

Exceptions

ArithmeticException if an error occurs during the instruction.