*Cosine similarity\r
\r
Using this comparison method, birthmarks must have name and its\r
-frequency. Threfore, elements of <f(p)> be a set of <(\{name_1,\r
+frequency. Therefore, elements of <f(p)> be a set of <(\{name_1,\r
freq_1\}, \{name_2, freq_2\}, ..., \{name_n, freq_n\})>.\r
\r
Next, if <f(p)> have name <FOO> and <f(q)> do not have <FOO>, we add\r