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iavf: iavf_client: use struct_size() helper
authorGustavo A. R. Silva <gustavo@embeddedor.com>
Fri, 29 Mar 2019 23:38:50 +0000 (16:38 -0700)
committerJeff Kirsher <jeffrey.t.kirsher@intel.com>
Fri, 31 May 2019 07:14:11 +0000 (00:14 -0700)
commit53462f0f4772c1e81786df1261e2009b44fed9f2
treef6438f8a8f6ea80dbb5228db1329aa481e3ed716
parent06665619cc8897d55eab5679b0927069dc345c19
iavf: iavf_client: use struct_size() helper

One of the more common cases of allocation size calculations is finding
the size of a structure that has a zero-sized array at the end, along
with memory for some number of elements for that array. For example:

struct foo {
    int stuff;
    struct boo entry[];
};

size = sizeof(struct foo) + count * sizeof(struct boo);

Instead of leaving these open-coded and prone to type mistakes, we can
now use the new struct_size() helper:

size = struct_size(instance, entry, count);

This code was detected with the help of Coccinelle.

Signed-off-by: "Gustavo A. R. Silva" <gustavo@embeddedor.com>
Tested-by: Andrew Bowers <andrewx.bowers@intel.com>
Signed-off-by: Jeff Kirsher <jeffrey.t.kirsher@intel.com>
drivers/net/ethernet/intel/iavf/iavf_client.c