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of: reserved_mem: Use stable allocation order
authorStephan Gerhold <stephan@gerhold.net>
Wed, 14 Jun 2023 19:20:43 +0000 (21:20 +0200)
committerRob Herring <robh@kernel.org>
Tue, 20 Jun 2023 15:34:58 +0000 (09:34 -0600)
sort() in Linux is based on heapsort which is not a stable sort
algorithm - equal elements are being reordered. For reserved memory in
the device tree this happens mainly for dynamic allocations: They do not
have an address to sort with, so they are reordered somewhat randomly
when adding/removing other unrelated reserved memory nodes.

Functionally this is not a big problem, but it's confusing during
development when all the addresses change after adding unrelated
reserved memory nodes.

Make the order stable by sorting dynamic allocations according to
the node order in the device tree. Static allocations are not affected
by this because they are still sorted by their (fixed) address.

Signed-off-by: Stephan Gerhold <stephan@gerhold.net>
Link: https://lore.kernel.org/r/20230510-dt-resv-bottom-up-v2-2-aeb2afc8ac25@gerhold.net
Signed-off-by: Rob Herring <robh@kernel.org>
drivers/of/of_reserved_mem.c

index 7f892c3..7ec94cf 100644 (file)
@@ -268,6 +268,11 @@ static int __init __rmem_cmp(const void *a, const void *b)
        if (ra->size > rb->size)
                return 1;
 
+       if (ra->fdt_node < rb->fdt_node)
+               return -1;
+       if (ra->fdt_node > rb->fdt_node)
+               return 1;
+
        return 0;
 }