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sched/fair: Fix condition of avg_load calculation
authorTao Zhou <ouwen210@hotmail.com>
Thu, 19 Mar 2020 03:39:20 +0000 (11:39 +0800)
committerPeter Zijlstra <peterz@infradead.org>
Fri, 20 Mar 2020 12:06:20 +0000 (13:06 +0100)
In update_sg_wakeup_stats(), the comment says:

Computing avg_load makes sense only when group is fully
busy or overloaded.

But, the code below this comment does not check like this.

From reading the code about avg_load in other functions, I
confirm that avg_load should be calculated in fully busy or
overloaded case. The comment is correct and the checking
condition is wrong. So, change that condition.

Fixes: 57abff067a08 ("sched/fair: Rework find_idlest_group()")
Signed-off-by: Tao Zhou <ouwen210@hotmail.com>
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Reviewed-by: Vincent Guittot <vincent.guittot@linaro.org>
Acked-by: Mel Gorman <mgorman@suse.de>
Link: https://lkml.kernel.org/r/Message-ID:
kernel/sched/fair.c

index 783356f..d7fb20a 100644 (file)
@@ -8631,7 +8631,8 @@ static inline void update_sg_wakeup_stats(struct sched_domain *sd,
         * Computing avg_load makes sense only when group is fully busy or
         * overloaded
         */
-       if (sgs->group_type < group_fully_busy)
+       if (sgs->group_type == group_fully_busy ||
+               sgs->group_type == group_overloaded)
                sgs->avg_load = (sgs->group_load * SCHED_CAPACITY_SCALE) /
                                sgs->group_capacity;
 }