help_oneline is declared and starts as:
static void help_oneline(const char *cmd, const cmdinfo_t *ct)
{
if (cmd) {
printf("%s ", cmd);
} else {
printf("%s ", ct->name);
if (ct->altname) {
printf("(or %s) ", ct->altname);
}
}
However, there are only two routes to help_oneline being called:
help_f -> help_all -> help_oneline(ct->name, ct)
help_f -> help_onecmd(argv[1], ct)
In the first case, 'cmd' and 'ct->name' are the same thing,
so it's impossible for the if (cmd) to be false and then validly
print ct->name - this is upsetting gcc
( https://gcc.gnu.org/bugzilla/show_bug.cgi?id=96739 )
In the second case, cmd is argv[1] and we know we've got argv[1]
so again (cmd) is non-NULL.
Simplify help_oneline by just printing cmd.
(Also strengthen argc check just to be pedantic)
Signed-off-by: Dr. David Alan Gilbert <dgilbert@redhat.com>
Message-Id: <
20200824102914.105619-1-dgilbert@redhat.com>
Signed-off-by: Kevin Wolf <kwolf@redhat.com>
static void help_oneline(const char *cmd, const cmdinfo_t *ct)
{
- if (cmd) {
- printf("%s ", cmd);
- } else {
- printf("%s ", ct->name);
- if (ct->altname) {
- printf("(or %s) ", ct->altname);
- }
- }
+ printf("%s ", cmd);
if (ct->args) {
printf("%s ", ct->args);
{
const cmdinfo_t *ct;
- if (argc == 1) {
+ if (argc < 2) {
help_all();
return 0;
}