From 8a8fd63734944bf6f7111596bd9cc9db6afb9b7c Mon Sep 17 00:00:00 2001 From: Anthony Liguori Date: Tue, 16 Apr 2013 09:45:15 -0500 Subject: [PATCH] qtest: don't use system command to avoid double fork Currently we waitpid on the child process we spawn off that does nothing more than system() another process. While this does not appear to be incorrect, it's wasteful and confusing so get rid of it. Signed-off-by: Anthony Liguori Message-id: 1366123521-4330-2-git-send-email-aliguori@us.ibm.com --- tests/libqtest.c | 11 ++++------- 1 file changed, 4 insertions(+), 7 deletions(-) diff --git a/tests/libqtest.c b/tests/libqtest.c index 389596a055..884f959992 100644 --- a/tests/libqtest.c +++ b/tests/libqtest.c @@ -107,7 +107,7 @@ static pid_t qtest_qemu_pid(QTestState *s) QTestState *qtest_init(const char *extra_args) { QTestState *s; - int sock, qmpsock, ret, i; + int sock, qmpsock, i; gchar *pid_file; gchar *command; const char *qemu_binary; @@ -136,10 +136,8 @@ QTestState *qtest_init(const char *extra_args) "%s", qemu_binary, s->socket_path, s->qmp_socket_path, pid_file, extra_args ?: ""); - - ret = system(command); - exit(ret); - g_free(command); + execlp("/bin/sh", "sh", "-c", command, NULL); + exit(1); } s->fd = socket_accept(sock); @@ -169,9 +167,8 @@ void qtest_quit(QTestState *s) pid_t pid = qtest_qemu_pid(s); if (pid != -1) { - /* kill QEMU, but wait for the child created by us to run system() */ kill(pid, SIGTERM); - waitpid(s->child_pid, &status, 0); + waitpid(pid, &status, 0); } unlink(s->pid_file); -- 2.11.0